luagc.GetAllGCObjects

table luagc.GetAllGCObjects( any targetObject )

Description

Returns a table containing all GCobjects.
The GClist always goes from newest to oldest GCobjects due to how the GCobjects are chained.

This function itself create a table which is why doing
luagc.GetAllGCObjects(luagc.GetCurrentGCHeadObject())
Will always have 1 object - which is the returned table.
You can do table.remove(gcList, 1) to remove the first entry to get rid of it.

Recently Added

This was recently added in version (0.8 - DEV).

Arguments

1any targetObject

If given a targetObject object, it will return all GCobjects until it reached the targetObject after which it'll stop.
(the targetObject won't be included in the result!)

Returns

1table objects

Example

An example usage

collectgarbage("stop") -- to not modify gc list local gcHead = luagc.GetCurrentGCHeadObject() function Example() -- 1 GCfunction return {} end Example() -- Returns 1 GCtable debug.setfenv(Example, {}) -- to avoid printing _G below - also creates 1 GCtable -- Now print all new GC objects created by our code above local gcList = luagc.GetAllGCObjects(gcHead) table.remove(gcList, 1) -- remove the gcList table from itself since it included as the first entry. for _, gcObject in ipairs(gcList) do print("object: " .. tostring(gcObject) .. " (type: " .. type(gcObject) .. ")") end

object: table: 0xf0b9fdea (type: table) object: table: 0xf09ffc3a (type: table) object: function: 0xf0bf9cb2 (type: function)